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Determine the slope-intercept form of the equation of the line parallel to y = x + 11 that passes through the point (–6, 2).

User DaveH
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2 Answers

7 votes

Answer:

y= -4/3x+ -6

Edge- correct

User Soeren
by
7.6k points
5 votes
we know that
the slope-intercept form of the equation of the line is
y=mx+b

if two lines are parallel both slopes are the same

step 1
find the slope of the line y = x + 11

the slope m=1

step 2
with the point (-6,2) and m=1 find the equation of a line
y=mx+b-------> 2=(1)*(-6)+b-----> 2=-6+b-----> b=2+6----> b=8

the equation of the line is
y=x+8

the answer is
y=x+8

User Justin Skiles
by
8.1k points

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