Question

Use the parabola tool to graph the quadratic function. f(x)=2x2+4x−16

Answer 1

The answer is (0,-18) (2,0). Sorry it's late

Answer 2

Refer the attached figure.

Explanation:

Given : Quadratic function
`f(x)=2x^2+4x-16`

To find : The graph of the quadratic function using parabola tool?

Solution :

The given function
`f(x)=2x^2+4x-16`

First we find the vertex form of the equation

`f(x)=2x^2+4x-16`

Where, a=2 ,b=4 , c=-16

Vertex is
`V=((-b)/(2a),f((-b)/(2a)))`

`(-b)/(2a)=(-4)/(2(2))=-1`

`f((-b)/(2a))=f(-1)=2(-1)^2+4(-1)-16=-18`

So, The vertex of the equation is (-1,-18)

Now, we find y- intercept by putting x=0 in the equation

`y=2(0)^2+4(0)-16`

`y=-16`

y- intercept (0,-16)

Now, we find x- intercept by putting y=0 in the equation

`2x^2+4x-16=0`

`x^2+2x-8=0`

`x^2+4x-2x-8=0`

`x(x+4)-2(x+4)=0`

`(x+4)(x-2)=0`

`x=-4,2`

x- intercepts are (-4,0) and (2,0)

Placing all the points and plot a graph.

Refer the attached figure below.