Hey there! :)
To find the equation of a line that passes through (2, -4) & (5, 13), we must first find the slope.
To find the slope, we must use the slope equation, which is : m = (y₂-y₁) / (x₂-x₁)
So, let's plug everything in!
m = (y₂ - y₁) / (x₂ - x₁)
m = (13 - (-4)) / (5 - 2)
Simplify.
m = (13 + 4) / 3
Simplify.
m = 17/3
So, our slope is 17/3!
Now, let's find the equation of the line using slope-intercept form.
Remember that slope-intercept form is : y=mx+b where m=slope, b=y-intercept.
Since we already have the slope, all we need to do is find the y-intercept.
To find the y-intercept, let's plug all of our known variables into y-intercept form, using the points (2, 4) and the slope 17/3.
y = mx + b
(4) = (17/3)(2) + b
Simplify.
4 = 24/3 + b
Simplify.
4 = 8 + b
Subtract 8 from both sides.
4 - 8 = b
Simplify.
-4 = b
So, our y-intercept is b!
Using our known variables (slope, y-intercept), we can very easily plug it into a new slope-intercept equation!
y = mx + b
So, since our slope is 17/3 and our y-intercept is -4, let's plug and chug!
y = 17/3x - 4 → our final answer
~Hope I helped!~