Question

A 5 kg rock is raised 28 m above the ground level. What is the change in its potential energy?

Answer 1

The change in potential energy of the 5 kg rock raised 28 m above the ground level is 1372 J.

Step-by-step explanation:

The change in potential energy of an object can be calculated using the formula:

ΔPE = mgh

Where:

1. ΔPE is the change in potential energy

2. m is the mass of the object (in this case, 5 kg)

3. g is the acceleration due to gravity

4. (approximately 9.8 m/s²)

5. h is the change in height (in this case, 28 m)

Using the values given, we can calculate the change in potential energy:

ΔPE = (5 kg) * (9.8 m/s²) * (28 m) = 1372 J

Therefore, the change in potential energy of the 5 kg rock raised 28 m above the ground level is 1372 J.

Answer 2

Let's assume that ground level is the height 0 meters. The change in potential energy is going to be gravitational potential energy, which is given by PE=mgh.
ΔPE=mgh-mgy
=mg(h-y)
=50(28-0)
=1400 J