155k views
0 votes
Please help with this
see attached below
Thanks to helpful users:)

Please help with this see attached below Thanks to helpful users:)-example-1
Please help with this see attached below Thanks to helpful users:)-example-1
Please help with this see attached below Thanks to helpful users:)-example-2
Please help with this see attached below Thanks to helpful users:)-example-3
Please help with this see attached below Thanks to helpful users:)-example-4
Please help with this see attached below Thanks to helpful users:)-example-5
User Tomaroo
by
6.1k points

2 Answers

2 votes
Part A the new function will be -16t^2 + 224t + 120

Part B The axis of symmetry ( x = 7) will be same for both graphs
The maximum value fr the new graph will be 904 seconds ( that is 120 more than the original graph).
The zeroes for the first graph are 0 and 14. For the second graph the first one will be negative and the second will be greater than 14 meters.


User Mike Roosa
by
6.8k points
2 votes
c.From the ground
f(7)=-16*7² +224*7=784 ft
If from 120 ft building - 784+120=904 ft
d. -16t(t-14), t=14 , to increase by 2 sec,
-16t(t-16)=-16t+256t
To make stay in the air longer by 2 sec , the initial velocity should be 256 feet/sec, if the company will be launching firework from the ground


User Barbiepylon
by
5.8k points