Solution
For this case we can find the area as the sum of the rectangle and the semicircle so we have this:
A1= 3in * 4in= 12 in^2
A2 = (pi/2) *(2in)^2 = 6.28 in^2
then the total area is:
A= A1+ A2= 12+ 6.28 in^2 = 18.28 in^2
And then the perimeter similarly we have:
P= 2*4 in + 2*3in + 2pi*(4in/2) = 8+ 6+ 12.56 in= 26.56in
Then the final answer is:
Area ~18.28 in^2 and Perimeter ~26.56 in