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Determine the number of x-intercepts that appear on a graph of each function. f (x) = (x - 6)2(x + 2)2

2 Answers

2 votes

Answer:

2

Explanation:

User Ravun
by
6.6k points
2 votes
The number of x-intercepts that appear on the graph of the function
f(x)=(x-6)^2(x+2)^2 is two (2): x=6 (multiplicity 2) and x=-2 (multiplicity 2)


Solution
x-intercepts:
f(x)=0→(x-6)^2 (x+2)^2 =0

Using that: If a . b =0→a=0 or b=0; with a=(x-6)^2 and b=(x+2)^2

(x-6)^2=0
Solving for x. Square root both sides of the equation:
sqrt[ (x-6)^2] = sqrt(0)→x-6=0
Adding 6 both sides of the equation:
x-6+6=0+6→x=6 Multiplicity 2

(x+2)^2=0
Solving for x. Square root both sides of the equation:
sqrt[ (x+2)^2] = sqrt(0)→x+2=0
Subtracting 2 both sides of the equation:
x+2-2=0-2→x=-2 Multiplicity 2
User Harish Pathak
by
6.4k points
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