Answer with Step-by-step explanation:
The fundamental theorem of algebra states that every non-constant single-variable polynomial with complex coefficients has at least one complex root. This includes polynomials with real coefficients, since every real number can be considered a complex number with its imaginary part equal to zero.
Hence, the given polynomial equation has atleast 1 real root and atmost 3 real roots
(9x + 7)(4x + 1)(3x + 4) = 0
On solving this, we get
9x+7=0 or 4x+1=0 or 3x+4=0
i.e. x= -7/9 or x= -1/4 or x= -4/3
As we can see all the roots are real
Hence, number of real roots are:
3