177k views
0 votes
Plz answer it........

Plz answer it........-example-1
User Pictoru
by
8.3k points

1 Answer

3 votes
Okay,
so,
The given expression is :

16{(a + b)}^(2) - 49 {(a - b)}^(2)

As 16 is sqaure of 4 and 49 is square of 7, then this whole expression could also be written as


{{((4)(a + b))}}^(2) - {{((7)(a - b))}}^(2)
Now,
as you might've notices by now that this expression is in the form of


{x}^(2) - {y}^(2)
And there's an alzebric identity about it. That is

{x}^(2) - {y}^(2) = (x + y)(x - y)
Now by using this alzebric identity. we're gonna split our expession as shown below:

(4(a + b) + 7(a - b)) * (4(a + b) - 7(a - b) \\ \\ = (4a + 4b + 7a - 7b) * (4a + 4b - 7a + 7b) \\ = (11a - 3b)( 11b - 3a)




By solving the last step i.e,
(11a-3b)(11b-3a)

we'll get,
121a^2 - 33ab -33b^2 -8ab

= 121a^2-33b^2 -41ab .


User Bitta
by
8.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories