Question

Consider the balanced chemical reaction below and determine the percent yield of sodium bromide if 2.36 moles of iron(iii) bromide yielded 6.14 moles of sodium bromide

2FeBr+3Na2S=Fe2S3+6NaBr

Answer 1

86.72

Step-by-step explanation:

Good luck

Answer 2

First the theoretical yield of Nabr
by use of mole ratio between FeBr3 and NaBr which is 2:6 the theoretical yield

=2.36 x6/2= 7.08 moles

the % yield = actual yield/ theoretical yield x 100

that is 6.14/7.08 x100= 86.72%