Question

6x - y =4 and y = 4x + 2. Solve the system and find x - 2y

Answer 1

`Point Form:(1,2)\\Equation Form:x=1,y=2`

Explanation:

Let's solve your system by substitution.

`6x-y=4;y=4x+2x-2y`

Step: Solve 6x−y=4for y:

`6x-y=46x-y+-6x=4+-6x`

`-y=-6x+4`

`(-y)/(-1) =(-6x+4)/(-1)`

`y=6x-4`

Step: Substitute 6x−4 for y in y=6x−2y:

`y=6x-2y\\6x-4=6x-2(6x-4)`

`6x-4=-6x+8`

`6x-4+6x=-6x+8+6x\\12x-4=8\\12x-4+4=8+4`

`12x=12\\(12x)/(12) =(12)/(12)`

Step: Substitute 1 for x in y=6x−4:

`y=6-4\\y=(6)(1)-4\\y=2`

Answer:

`x=1 , y=2`

Hope this helps :)

-ilovejiminssi♡

Answer 2

x = 3

x - 2y = -25

Explanation:

Since y = 4x + 2 put (4x + 2) into the first equation in place of y:

6x - (4x + 2) = 4

To get rid of the parenthesis change 4x to -4x and 2 to -2:

6x - 4x - 2 = 4

If you combine the x’s you will now have only 2x

2x - 2 = 4

To get x by itself we add 2 to both sides

2x = 6

Divide by 2 on both sides:

x = 3

_______________________________

For the last equation (x - 2y) we put (4x + 2) in place of y again:

x - 2[4x + 2]

We know the value of x already:

3 - 2[4(3) + 2]

Now solve for the things in parenthesis:

3 - 2(14)

3 - 28

Subtract to get the answer:

-25