Question

The amount of pressure required to move a 6800 lb force with a 6" d piston is ___ psi.

Answer 1

The pressure required to move a 6800 lb force with a 6" diameter piston is approximately 1650459.26 Pa.

Step-by-step explanation:

The amount of pressure required to move a 6800 lb force with a 6" diameter piston can be calculated using the formula:

Pressure = Force / Area

First, we need to convert the force to Newtons. Since 1 lb = 0.454 kg and 1 kg = 9.8 N, the force in Newtons is:

6800 lb x 0.454 kg/lb x 9.8 N/kg = 30103.76 N

The area of the piston can be calculated using the formula:

Area = π x radius^2

Since the diameter of the piston is 6", the radius is 3" or 0.0762 m. Therefore, the area of the piston is:

Area = π x (0.0762 m)^2 = 0.01824 m^2

Finally, we can calculate the pressure:

Pressure = 30103.76 N / 0.01824 m^2 = 1650459.26 Pa

Therefore, the amount of pressure required to move the 6800 lb force with a 6" diameter piston is approximately 1650459.26 Pa or psi.

Answer 2

The pressure needed in PSI = Pounds of force needed divided by the cylinder Area
The Cylinder rod Area is 21.19 sq inches
Thus, the pressure= 6800/21.19
= 320.91 PSI