Final answer:
The pressure required to move a 6800 lb force with a 6" diameter piston is approximately 1650459.26 Pa.
Step-by-step explanation:
The amount of pressure required to move a 6800 lb force with a 6" diameter piston can be calculated using the formula:
Pressure = Force / Area
First, we need to convert the force to Newtons. Since 1 lb = 0.454 kg and 1 kg = 9.8 N, the force in Newtons is:
6800 lb x 0.454 kg/lb x 9.8 N/kg = 30103.76 N
The area of the piston can be calculated using the formula:
Area = π x radius^2
Since the diameter of the piston is 6", the radius is 3" or 0.0762 m. Therefore, the area of the piston is:
Area = π x (0.0762 m)^2 = 0.01824 m^2
Finally, we can calculate the pressure:
Pressure = 30103.76 N / 0.01824 m^2 = 1650459.26 Pa
Therefore, the amount of pressure required to move the 6800 lb force with a 6" diameter piston is approximately 1650459.26 Pa or psi.