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Use the dot product to find |v| when v=(7,24) a. 25 b. -17 c. 31 d. 625

2 Answers

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THE ANSWER IS A

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User Darjan Bogdan
by
8.6k points
0 votes
Dot product has the following definition:

\textbf{a}\cdot \textbf{b}=|a| |b| cos(\theta)
Where
\theta is the angle between two vectors and
|a|, |b| are their lengths.
The dot product of the vector with itself will give you the square of its length.

\textbf{a}\cdot \textbf{a}=|a| |a| cos(0)=|a| |a|=|a|^2
If you are given end points of a vector dot product is defined in the following fashion:

a=[a_1,a_2,a_3]\\ b=[b_1,b_2,b_3]\\ \textbf{a}\cdot \textbf{b}=\textbf{a} \sum b_i \textbf{e}_i= \sum b_i (\textbf{a} \cdot \textbf{e}_i)= \sum b_i a_i

\textbf{a}\cdot \textbf{a}=\sum a_i^2
Where
\textbf{e}_i are unit vectors. These are vectors of a unit length and they span in direction of a coordinate axis (if you are working with Cartesian coordinate system). If you do a dot product of a unit vector of x-axis and unit vector of y-axis you get zero, because the angle between them is 90 degrees.
Now we can apply the above formula to this problem:

v= [7,24]\\ \textbf{v}\cdot \textbf{v}=|v|^2=(7\cdot 7)+(24\cdot 24)=625\\ |v|=√(625)=25
So the answer is A.
This formula will give you the length of a vector in Euclidian geometry:

|a|=\sqrt{a_1^2+a_2^2+a_3^3
Where
a_i are the coordinates of the end point of that vector.
User Dmytro Bondarenko
by
8.5k points

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