Question

(i) (a) what is the force per meter of length on a straight wire carrying a 9.75 a current when perpendicular to a 0.81 t uniform magnetic field?

Answer 1

The force generated by a magnetic field B perpendicular to a wire carrying a current I is

`F=ILB`
where L is the length of the wire.

If we divide both sides for L, we get

`(F)/(L)=IB`
where the ratio on the left is the force per meter of length, which is exactly what we want to find. So:

`(F)/(L)=IB=(9.75 A)(0.81 A)=7.90 N/m`