192k views
5 votes
How many factors in the expression 8(x+4)(y+4)z^2+4z+7) have exactly two terms

1 Answer

4 votes
The answer is: " 2 {two}" .
_________________________________________________________
There are "2 {two}" factors in the expression:
_________________________________________________________
→ " 8(x + 4)(y + 4)(z² + 4z + 7) " ;

that have "exactly two terms". The factors are:
_________________________________________________________
" (x + 4) " ; and: " (y + 4) " .
_________________________________________________________
Note:
________________________________________________________
Among the 4 (four) factors; the following 2 (TWO) factors have exactly 2 (two) terms:

" (x + 4)" ; The 2 (two) terms are "x" and "4" ; AND:

" (y + 4)" ; → The 2 (two) terms are "y" and "4" .
_________________________________________________________
Step-by-step explanation:
_________________________________________________________
We are given the expression:

" 8(x + 4)(y + 4)(z² + 4z + 7) " ;
_________________________________________________________
There are 4 (four) factors in this expression; which are:

1) " 8 " ; 2) "(x + 4)" ; 3) "(y + 4)" ; and: 4) "(z² + 4z + 7)" .
_________________________________________________________
Among the 4 (four) factors; the following factors have exactly 2 (two) terms:

" (x + 4)" ; The 2 (two) terms are "x" and "4" ; AND:

" (y + 4)" ; The 2 (two) terms are "y" and "4" .
_________________________________________________________

Note: Let us consider the remaining 2 (two) factors in the given expression:
" 8(x + 4)(y + 4)(z² + 4z + 7) "

Consider the factor: " 8 " ; This factor has only one term— " 8 " ;
→ { NOT "2 (two) terms" } ; so we can rule out this option.

The last remaining factor is: " (z² + 4z + 7) " .

This factor has "3 (three) terms" ; which are:

1) " " ; 2) "4z" ; and: 3) " 7 " ;

{ NOT "2 (two) terms" } ; so we can rule out this option.
___________________________________________________________
User Max Sindwani
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories