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Which statement is always true about the graph of an equation in the form y=kx?

a)The point (0,k) is on the graph.
b)The point (1,1) is on the graph.
c)The point (k,0) is on the graph
d)The point (0,0) is on the graph.

User Ddoo
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2 Answers

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The correct answer is Choice D.

The equation y = kx is a proportional graph. It means that you multiply x by a number and you have k.

The point (0, 0) will always be on the graph, because no matter what K is, if you are multiplying by 0 for x, you will get 0 for y.
User DLRdave
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4 votes

Answer:

d)The point (0,0) is on the graph.

Explanation:

Select statement is always true about the graph of an equation in the form y=kx

(0,k) , x=0 and y=k

LEts plug in x=0 in y= kx

y=k(0) =0, so the point (0,k) on the graph of y=kx is not true

(1,1) , x=1 and y=1

LEts plug in x=1 in y= kx

y=k(1) =k, so the point (1,1) on the graph of y=kx is not true

(k,0) , x=k and y=0

LEts plug in x=k in y= kx

y=k(k) =k^2, so the point (k,0) on the graph of y=kx is not true

(0,0) , x=0 and y=0

Lets plug in x=0 in y= kx

y=k(0) =0, so the point (0,0) on the graph of y=kx is true

User Martin Marinov
by
6.2k points
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