Answer:
d)The point (0,0) is on the graph.
Explanation:
Select statement is always true about the graph of an equation in the form y=kx
(0,k) , x=0 and y=k
LEts plug in x=0 in y= kx
y=k(0) =0, so the point (0,k) on the graph of y=kx is not true
(1,1) , x=1 and y=1
LEts plug in x=1 in y= kx
y=k(1) =k, so the point (1,1) on the graph of y=kx is not true
(k,0) , x=k and y=0
LEts plug in x=k in y= kx
y=k(k) =k^2, so the point (k,0) on the graph of y=kx is not true
(0,0) , x=0 and y=0
Lets plug in x=0 in y= kx
y=k(0) =0, so the point (0,0) on the graph of y=kx is true