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Calculate the ph of a solution that has a [oh-] = 2.50 x 10-4m.

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It is so simple when you have [OH-] so you will use it to get POH from this formula:

POH = -㏒[OH]

= -㏒ 2.5 x 10^-4

= 3.6

when PH + POH = 14

∴ PH = 14 - POH

= 14 - 3.6 = 10.4
User Shari
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