Question

Determine the discriminant for the quadratic equation –3 = x2 + 4x + 1. Based on the discriminant value, how many real number solutions does the equation have?

Answer 1

Discriminant = b^2 - 4ac = 4^2 - 4*1*4 = 0
There are 2 real solutions
They are x = -2 (duplicity 2).

Answer 2

x^2 + 4x + 4 = 0
d = b^2 - 4ac, where a = 1, b = 4 and c = 4
d = 4^2 - 4 x 1 x 4
d = 16 - 16 = 0
Since d = 0, there is one real solution to the equation
hope it helps