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Calculate the force experienced by a positive test charge of 8.1 × 10-9 coulombs if the electric field strength is 9.4 × 107 newtons/coulomb.
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Calculate the force experienced by a positive test charge of 8.1 × 10-9 coulombs if the electric field strength is 9.4 × 107 newtons/coulomb.

User Keshan
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C.) 7.6×10^-1 :) your welcome

User Swerly
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The electric force exerted by an electric field of intensity E on a charge q is equal to the product between E and q, so:

F=qE=(8.1 \cdot 10^(-9)C)(9.4 \cdot 10^7 N/C)=0.76 N
User Ninca
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