Register
Calculate the force experienced by a positive test charge of 8.1 × 10-9 coulombs if the electric field strength is 9.4 × 107 newtons/coulomb.
81.6k views
4 votes
Calculate the force experienced by a positive test charge of 8.1 × 10-9 coulombs if the electric field strength is 9.4 × 107 newtons/coulomb.

User Keshan
by
8.3k points

2 Answers

6 votes
C.) 7.6×10^-1 :) your welcome

User Swerly
by
8.7k points
2 votes
The electric force exerted by an electric field of intensity E on a charge q is equal to the product between E and q, so:

F=qE=(8.1 \cdot 10^(-9)C)(9.4 \cdot 10^7 N/C)=0.76 N
User Ninca
by
8.2k points
← Prev Question Next Question →

Related questions

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.5m questions

12.2m answers

Other Questions

At sea level, water boils at 100 degrees celcius and methane  boiled at -161 degrees celcius. Which of these substances has a stronger force of attraction between its particles? Explain your answer
Physical properties of minerals graphic organizer
A snowball is launched horizontally from the top of a building at v = 16.9 m/s. If it lands d = 44 meters from the bottom, how high (in m) was the building?
What type of rock is the Haystack rock (igneous, Metamorphic, or Sedimentary)
what is a device that transforms thermal energy to mechanical energy
Link Copied!