Question

Given the graph below, find WV.

Answer 1

According to the a^2+b^2=c^2 c= square root of(2^2+6^2)=sqrt{40}or2 sqrt{10} approximately 6.325. Hope this thanks.

Answer 2

`WV=√(40)\approx 6.32`

Explanation:

We have been given a graph of coordinate plane. We are asked to find the length of segment WV.

Point W(-2,-2) and point V(0,4).

We will use distance formula to solve our given problem.

`\text{Distance}=√((x_2-x_1)^2+(y_2-y_1)^2)`

`\text{Distance}=√(((0-(-2))^2+4-(-2))^2)`

`\text{Distance}=√((+2)^2+(4+2)^2)`

`\text{Distance}=√(2^2+6^2)`

`\text{Distance}=√(4+36)`

`\text{Distance}=√(40)`

`\text{Distance}=6.324555`

`\text{Distance}\approx 6.32`

Therefore, the length of segment WV is approximately 6.32 units.