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Y=x^2+3x-7 y-5x+8=0 how many solutions are there
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Y=x^2+3x-7 y-5x+8=0 how many solutions are there
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Feb 13, 2019
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Y=x^2+3x-7 y-5x+8=0 how many solutions are there
Mathematics
middle-school
Kumaresh Babu N S
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Kumaresh Babu N S
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X^2+3×-7=5x-8
X^2-2x+1=0
(X-1)(x-1)=0
X=1 x=1
Y=1^2+3*1-7
Y=1+3-7
Y=4-7
Y=-3
×=1 y=-3
Solution = (1,-3)
Answer= one solution
Xu Yin
answered
Feb 17, 2019
by
Xu Yin
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