Y=x^2+3x-7 y-5x+8=0 how many solutions are there

asked Feb 13, 2019 201k views

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6 votes

X^2+3×-7=5x-8
X^2-2x+1=0
(X-1)(x-1)=0
X=1 x=1

Y=1^2+3*1-7
Y=1+3-7
Y=4-7
Y=-3

×=1 y=-3
Solution = (1,-3)
Answer= one solution

Xu Yin answered Feb 17, 2019

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