Question

The area of a rectangle is 63ft ^2 and the length of the rectangle is 5ft more than double the width. Find the dimensions of the rectangle.

Answer 1

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Define Length and Width
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Let the width be x
Width = x
Length = 2x + 5

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Form equation and solve for x
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x(2x + 5) = 63
2x² + 5x = 63
2x² + 5x - 63 = 0
(x+7)(2x-9) = 0
x = -7 (rejected, length cannot be negative) or 2x - 9 = 0
2x - 9 = 0
2x = 9
x = 9 ÷ 2
x = 4.5 ft

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Find Length and Width
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Width = x = 4.5 ft
Length = 2x + 5 = 2(4.5) + 5 = 14 ft

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Answer: Width = 4.5 ft , Length = 14 ft
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