Answer:

Explanation:
Let us suppose a ΔABC , whose interior angles are A , B and C
Let their sides are measured as
a , b and c
where a is the side opposite to ∠A and so on.
Now there exist a formula , known as Law of cosine ,which helps us to determine the value of any angle , if all the sides of the triangle is given .
This formula is described as under

Above formula gives to cosine of ∠A, similarly we have formula for ∠B and ∠C

