Answer: D. AB congruent to DE
Explanation:
Given: ΔABC congruent to ΔTUV and ΔTUV congruent to ΔDEF ,
Since we know that the corresponding parts of congruent triangles are congruent.
Then, If ΔABC≅ ΔTUV
⇒AB≅TU......................................(1)
BC≅UV
AC≅TV
If ΔTUV ≅ ΔDEF
⇒ TU≅DE....................................................(2)
Applying transitive property of congruence in (1) and (2), we get
AB≅DE
UV≅EF
TV≅DF