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3 votes
25 POINTS! What is the distance between the points (2, 3) and (5, -4)? (XY AXIS)

User Weyhan
by
6.3k points

2 Answers

0 votes

A=(2,3)\qquad\qquad B=(5,-4)\\\\\\d(A,B)=√((5-2)^2+(-4-3)^2)=√(3^2+(-7)^2)=√(9+49)=\\\\=\boxed{√(58)\approx7.61}
3 votes
the distance could be calculated as follows:
d =
\sqrt{ (5-2)^(2) + (-4-3)^2} }
d =
\sqrt{ 3^(2) + (-7)^(2)
d =
√(58)
User Martinkabe
by
6.7k points
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