Complete the square to solve the equation below.check all that apply. x2 - 10x - 1 = 13

Question

asked Oct 11, 2019 119k views

2 Answers

CosmosKey · Answer 1 · 2019-10-13T22:21:24+0000

Answer:

Complete square:
(x-5)^2=39

Solutions:
$x=5\pm√(39)$

Explanation:

We have been given an equation
x^2-10x-1=13 . We are asked to complete the square.

First of all, we will add 1 to both sides of our given equation.

x^2-10x-1+1=13+1

x^2-10x=14

Now we will add
((b)/(2))^2 to both sides of our equation. We can see that the value of b is 10.

((10)/(2))^2=5^2=25

Upon adding 25 on both sides of our equation we will get,

x^2-10x+25=14+25

x^2-10x+25=39

(x-5)^2=39

Taking square root of both sides we will get,

(x-5)=√(39)

$(x-5)=\pm√(39)$

$x-5=\pm√(39)$

Adding 5 on both sides of our equation we will get.

$x-5+5=5\pm√(39)$

$x=5\pm√(39)$

Therefore, solutions for our given equation are
$x=5\pm√(39)$ .

Lucamug · Answer 2 · 2019-10-14T17:53:06+0000

x² -10x -1 = 13
x² -10x = 14
x² -10x +25 = 39 . . . . . add (10/2)² to complete the square
(x -5)² = 39
x -5 = ±√39
x = 5 ±√39