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What is the kinetic energy of a 74.0 kg man traveling in a car at a speed of 52.0 m/s?

2 Answers

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Final answer:

The kinetic energy of a 74.0 kg man traveling in a car at 52.0 m/s is 100,048 J (Joules), calculated using the formula KE = ½mv².

Step-by-step explanation:

The kinetic energy (KE) of an object can be calculated using the formula KE = ½mv², where m is the mass of the object and v is its velocity. For a 74.0 kg man traveling in a car at a speed of 52.0 m/s, we can plug these values into the formula:

KE = ½ × 74.0 kg × (52.0 m/s)²

KE = ½ × 74.0 kg × 2704 m²/s²

KE = ½ × 74.0 kg × 2704

KE = 37.0 kg × 2704

KE = 100,048 J (Joules)

Therefore, the kinetic energy of the man traveling in the car is 100,048 J (or 100.048 kJ).

User Wildan Muhlis
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Kinetic energy = 1/2mv^2
Mass m=74kg
Velocity C=52m/s
K.E= 0.5*74*52*52
K.E=100048J or 100.048kJ
User Jaredsmith
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4.1k points