Question

What is the equation of the axis of symmetry for the parabola Y equals 1/2 parentheses X -3 in parentheses squared +5

Answer 1

`\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \boxed{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k})\\\\ -------------------------------\\\\ y=\cfrac{1}{2}(x-\stackrel{h}{3})^2+\stackrel{k}{5}\qquad \qquad vertex~(3,5)`

since the squared variable in this case is the "x", that means is a vertical parabola, and so the axis of symmetry is the vertical line running over the x-coordinate of the vertex.

since the x-coordinate is 3, then x = 3.