Question

Consider a situation in which 136 g of p4 are exposed to 144 g of o2.what is the maximum number of moles of p2o5 that can theoretically be made from 136 g of p4 and excess oxygen?

Answer 1

First write a balanced equation...

P4 + 5 O2 ⇒ 2P2O5

mole of P4 = 136 ÷ (4×31) = 1.09677

MOLE RATION OF P4 : P2O5 IS 1:2
THAT IS 1 mole of p4 reacts to give 2 moleof p2o5
∴ 1.09677 mole............................. (2×1.09677) =2.19....mole

maximum number of mole = 2.19 mol