Question

Find the quotient.

48j 5 k 2 ÷ (-3j 3 k)

A. -16j2k
B. -16j3k2
C. -16j3k

Answer 1

A.  Divide the constant parts (48/-3 = -16), then divide each variable term separately (j^5/j^3 = j^2, and k^2/k = k)

Answer 2

correct option is A)
`-16j^(2)k`

Explanation:

We need to find the quotient of
`(48j^(5)k^(2))/(-3j^(3)k)`

Since,
`(a^(m))/(a^(n))=a^(m-n)`

first solve the like terms,

`(48j^(5-3)k^(2-1))/(-3)`

`(48j^(2)k)/(-3)`

Simplify the further above expression,

`-16j^(2)k`

Hence, correct option is A)
`-16j^(2)k`