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The "k" value moves the graph left or right.

TRUE
FALSE

What is the transformation that occurs to the equation y = (1/2)^x y equals one-half to the x power if the equation changes to y equals one-half to the negative x plus 1 power y = (1/2) ^ -x+1 ?
The graph is reflected across the y-axis and moves 1 unit to the left.
The graph is reflected across the y-axis and moves 1 unit to the right.
The graph is reflected across the x-axis and moves 1 unit to the right.
The graph is reflected across the x-axis and moves 1 unit to the left.

What is the transformation that occurs to the equation y = 2x if the equation changes to y = -2x+1 - 1?

The transformation moves the graph 1 unit to the left and 1 unit down.
The transformation moves the graph 1 unit to the left, 1 unit down and reflects that graph across the y-axis.
The transformation moves the graph 1 unit to the left, 1 unit down and reflects that graph across the x-axis.
The transformation moves the graph 1 unit to the right, 1 unit down and reflects that graph across the x-axis.

The domain of all exponential functions is x > 0.
TRUE
FALSE

Find the range of the function y = -2x + 2.
y < 2
y ≤ 2
y > 2
y ≥ 2

What is the domain for the function f(x) = 2x-5?
All Real Numbers
x > 0
x < 0
x > 1

1 Answer

5 votes
It is actually a false statement that the "k" value moves the graph left or right. The "k" value can always move up or down the graph depending on the co-efficient. The correct option among the two options that are given in the question is the second option. i hope that this is the answer that has come to your desired help. 2.the graph is reflected across the y-axis and moves 1 unit to the right.3.The transformation moves the graph 1 unit to the left, 1 unit down and reflects that graph across the y-axis.4.false 5y ≤ 2 6.x > 0 I HOPE THIS HELP YOU
User Hamidreza Salehi
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