Question

Calculate the number of carbon atoms in 5.6 liter of acetylene

Answer 1

Molar volume on standard temperature and pressure is 22,4 mol/L.
V(C₂H₂) = 5,6 L.
n(C₂H₂) = V(C₂H₂) ÷ Vm.
n(C₂H₂) = 5,6 L ÷ 22,4 mol/L.
n(C₂H₂) = 0,25 mol.
n(C₂H₂) . n(C) = 1 : 2.
n(C) = 2 · 0,25 mol = 0,5 mol.
N(C) = n(C) · Na.
N(C) = 0,5 mol · 6,022·10²³ 1/mol.
N(C) = 3,011·10²³ atoms of carbon in acetylene.