Question

A sample of methane gas, ch4(g), occupies a volume of 60.3 l at a pressure of 469 torr and a temperature of 29.3°c. what would be its temperature at a pressure of 243 torr and volume of 60.3 l?

Answer 1

Answer: The temperature when the volume and pressure has changed is -116.4°C

Step-by-step explanation:

To calculate the temperature when pressure and volume has changed, we use the equation given by combined gas law. The equation follows:

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

where,

`P_1,V_1\text{ and }T_1` are the initial pressure, volume and temperature of the gas

`P_2,V_2\text{ and }T_2` are the final pressure, volume and temperature of the gas

We are given:

`P_1=469torr\\V_1=60.3L\\T_1=29.3^oC=[29.3+273]K=302.3K\\P_2=243torr\\V_2=60.3L\\T_2=?K`

Putting values in above equation, we get:

`(469torr* 60.3L)/(302.3K)=(243torr* 60.3L)/(T_2)\\\\T_2=156.63K=-116.37^oC`

Hence, the temperature when the volume and pressure has changed is -116.4°C