Answer: The interval would be [71,107]
Explanation:
Since we ave given that
Scores received in 3 exams are 99%, 80%, and 70%.
To receive a grade of B in the class, he must have an average exam score between 80% and 89% for all 4 exams for all 4 exams.
So, Minimum marks he needs for all 4 exams is given by

Maximum marks he needs for all 4 exams is given by

And his total marks in 3 exams is

Minimum marks he needs in final exam is given by

Maximum marks he needs in final exam is given by

Hence, the interval would be [71,107]