Question

What is the molarity of a solution with 1.43 moles of sodium chloride in 0.875 liters of solution?

Answer 1

1.63 M

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Equality Properties

• Multiplication Property of Equality
• Division Property of Equality
• Addition Property of Equality
• Subtract Property of Equality

Chemistry

Unit 0

• Reading a Periodic Table
• Writing Compounds

Aqueous Solutions

• Molarity = moles of solute / liters of solution

Step-by-step explanation:

Step 1: Define

1.43 mol NaCl (sodium chloride)

0.875 L solution

Step 2: Find M

1. Substitute [M]: x M = 1.43 mol NaCl / 0.875 L
2. Divide: x = 1.63429 M

Step 3: Check

Follow sig fig rules and round. We are given 3 sig figs.

1.63429 M ≈ 1.63 M