Question

3. If you send a sound wave of the same wavelength (λ = 2.00 m) through air, helium, and carbon dioxide, describe how the pitch of the sound will compare through each medium. Use calculations and your data to explain

Answer 1

F = v / w

Air: 343m/s / 2.0 m = 171.5/s

Helium: 1007m/s / 2.0 m = 503.5/s

Carbon Dioxide: 267m/s / 2.0 m = 133.5 /s

Step-by-step explanation:

Answer 2

The speed of sound is in the gas is given with this formula:

`v=\sqrt{(\gamma RT)/(M)}`
Where T is the temperature, M is the molar mass of the gas, R is universal gas constant and
`\gamma` is heat capacity ratio.
We can find the speed of the sound in different gasses online ( you could also calculate it using above formula).

`Helium: v_h=1007(m)/(s)\\ Air: v_a=343 (m)/(s)\\ Carbon Dioxide: v_c=267(m)/(s)`
We know that pitch, wavelength, and speed of the sound are related:

`v=f\lambda`
Because our wavelentgh is the same the frequency must be different.

`v=f \lambda\\ f=(v)/(\lambda)`

`Helium: f_h=(1007)/(2)=503.5Hz\\ Air: f_a=(343)/(2)=171.2Hz \\ Carbon Dioxide: f_c=(267)/(2)=133.5Hz`