234k views
5 votes
The numerator and denominator of a fraction are in the ratio of 3 to 5. If the numerator and denominator are both decreased by 2, the fraction is now equal to .

If n = the numerator and d = the denominator, which of the following systems of equations could be used to solve the problem?

5n = 3d and n - 2 = 2d - 4
5n = 3d and 2n - 4 = d - 2
3n = 5d and 2n - 4 = d - 2

2 Answers

3 votes

Answer:

A 5n=3d and n-2=2d-4

Explanation:

User Steven Koch
by
8.3k points
6 votes
You probably missed that when the numerator and denominator are both decreased by 2, the new fraction is now equal to 1/2.

The numerator of the fraction is "n" and the denominator of the fractions is "d". Initially the numerator and denominator are in the ratio 3 to 5. In equation form we can state this as:


n:d=3:5 \\ \\ (n)/(d)= (3)/(5) \\ \\ 5n=3d

When both numerator and denominator are decreased by 2, the new numerator will be n-2 and denominator will be d-2. These numerator and denominators are in ratio 1 to 2. In equation form we can write this as:


n-2:d-2=1:2 \\ \\ (n-2)/(d-2) = (1)/(2) \\ \\ 2(n-2)=1(d-2) \\ \\ 2n-4=d-2

This is our second equation. Thus the two equation which can be used to solve the problem are:

5n = 3d
and
2n - 4 = d - 2
User SebastianG
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories