Question

Quadrilateral RSTU has vertices R (-3, 1) , S (-2, 3) , T (2, 3) , and U (3, 1). If you translate the quadrilateral four units down, what are the vertices of R'S'T'U'?

R' (-3, -3) , S' (-2, -1) , T '(2, -1) , and U' (3, -3)

R' (1, 1) , S' (2, 3) , T '(6, 3) , and U '(7, 1)

R' (-7, 1) , S' (-6, 3) , T '(-2, 3) , and U '(-1, 1)

R (-3, 3) , S (-2, 1) , T (2, 1) , and U (3, 3)
@Squirrels @tkhunny,

Answer 1

The correct option is 1.

Step-by-step explanation:

The vertices of quadrilateral RSTU are R (-3, 1) , S (-2, 3) , T (2, 3) , and U (3, 1).

It is given that quadrilateral RSTU translate four units down to get R'S'T'U'.

The relation between the vertices of RSTU and R'S'T'U' is

`(x,y)\rightarrow (x,y-4)`

The vertices of R'S'T'U' are

`R(-3,1)\rightarrow R'(-3,1-4)=R'(-3,-3)`

`S(-2,3)\rightarrow S'(-2,3-4)=S'(-2,-1)`

`T(2,3)\rightarrow T'(2,3-4)=T'(2,-1)`

`U(3,1)\rightarrow U'(3,1-4)=R'(3,-3)`

The vertices of R'S'T'U' are R' (-3, -3) , S' (-2, -1) , T '(2, -1) , and U' (3, -3).

Therefore the correct option is 1.

Answer 2

Answer:
First option

Step-by-step explanation:
Translating a point four units downwards means that:
the x-coordinate would stay the same
the y coordinate will be decreased by 4

Now, for the given points:
Point R (-3,1)
x coordinate o R' = x coordinate of R = -3
y cordinate of R' = y coordinate of R - 4 = 1 - 4 = -3
R' is (-3 , -3)

Point S (-2,3)
x coordinate of S' = x coordinate of S = -2
y coordinate of S' = y coordinate of S - 4 = 3 - 4 = -1
S' is (-2 , -1)

Point T (2,3)
x coordinate of T' = x coordinate of T = 2
y coordinate of T' = y coordinate of T - 4 = 3 - 4 = -1
T' is (2 , -1)

Point U (3,1)
x coordinate of U' = x coordinate of U = 3
y coordinate of U' = y coordinate of U - 4 = 1 - 4 = -3
U' is (3 , -3)

Comparing the calculated values with the given ones, we will find that the correct choice is the first one.

Hope this helps :)