To find the area of the triangle shown we have to find the length of a and the base.
a can be found using the sine function. Recall sin = (opp)/(hyp)
Here




The base can be found using the sin of 30 degrees as this is a 30-60-90 right triangle.



The area of the triangle in the picture is given by

.
The base of the pyramid is a hexagon which can be divided into 6 triangles each of which is double the area of the one we just found. So the area of the base = 2(area of the triangle we found)(6) =
