Question

The distance covered by the car is x² + 2x - 15 kilometers at (x - 3) hours. Find the Speed of the car.

The length of a paper is 4 units longer than its width. If the Area of the paper is 77 square units, what is the measure of the length of the paper?



Helpp plss ​

Answer 1

• Distance=x^2+2x-15
• Time=(x-3)h

Speed=Distance/Time

`\\ \tt\longmapsto Speed=(x^2+2x-15)/(x-3)`

`\\ \tt\longmapsto Speed=(x+5)km/h`

#2

• W be x
• L be x+4

AtQ

`\\ \tt\longmapsto x(x+4)=77`

`\\ \tt\longmapsto x^2+4x=77`

`\\ \tt\longmapsto x^2+4x-77=0`

`\\ \tt\longmapsto x^2+11x-7x-77=0`

`\\ \tt\longmapsto x(x+11)-7(x+11)=0`

`\\ \tt\longmapsto x-7(x+11)=0`

• Take it positive

`\\ \tt\longmapsto x=7`

• L=x+4=7+4=11units