Question

What is the equation of the line that is perpendicular to

the given line and passes through the point (2, 6)?

Answer 1

x = 2

Explanation:

The given line is parallel to X-axis, so its equation is y = b (b is its intersect of Y-axis)

Therefore the perpendicular line has to be parallel to Y-axis, so its equation will be x = x₀, where x₀ is its intersect of X-axis and x-coordinate of any point it passes through.

(2, 6) ⇒ x₀ = 2

so the equation is

x = 2