Question

Express 18.48 ( 48 bar) in the form of p/q where p and q are integers and q is not equal to 0.

Answer 1

Let the number be x
100x=1848.48. (1)
x=18.48. (2)
subtract 2 from 1

99x=1830.00
x=1830/99

Answer 2

We have to express
`18.\bar{48}` in the form of
`(p)/(q)` where p and q are integers and q is not equal to zero.

Let x =
`18.\bar{48}`

Multiplying the given equation by 100, we get

`100x = 1848.48484848...`

`100x = 1830+ 18.48484848...`

`100x = 1830+ 18.\bar{48}`

`100x = 1830+ x`

`99x=1830`

`x=(1830)/(99)`

Therefore,
`18.\bar{48}` is represented as
`x=(1830)/(99)` in the form of
`(p)/(q)`