40 g of calcium reacts with 71 g of chlorine to produce _____ g of calcium chloride

Question

asked Sep 5, 2019 131k views

2 Answers

Shariq Ansari · Answer 1 · 2019-09-10T05:43:29+0000

Answer: 111 g

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number
6.023* 10^(23) of particles.

To calculate the moles, we use the equation:

$\text{Number of moles of calcium}=\frac{\text{Given mass}}{\text {Molar mass}}=(40g)/(40g/mol)=1mole$

$\text{Number of moles of chlorine}=\frac{\text{Given mass}}{\text {Molar mass}}=(71g)/(71g/mol)=1mole$

$Ca+Cl_2\rightarrow CaCl_2$

1 moles of calcium react with 1 mole of chlorine to give 1 mole of calcium chloride.

Mass of calcium chloride =
$moles* {\text {molar mass}}=1mol* 111g/mol=111g$

Thus 111 g of calcium chloride is produced.