Question

40 g of calcium reacts with 71 g of chlorine to produce _____ g of calcium chloride

Answer 1

The answer is 111g of calcium chloride

Answer 2

Answer: 111 g

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number
`6.023* 10^(23)` of particles.

To calculate the moles, we use the equation:

`\text{Number of moles of calcium}=\frac{\text{Given mass}}{\text {Molar mass}}=(40g)/(40g/mol)=1mole`

`\text{Number of moles of chlorine}=\frac{\text{Given mass}}{\text {Molar mass}}=(71g)/(71g/mol)=1mole`

`Ca+Cl_2\rightarrow CaCl_2`

1 moles of calcium react with 1 mole of chlorine to give 1 mole of calcium chloride.

Mass of calcium chloride =
`moles* {\text {molar mass}}=1mol* 111g/mol=111g`

Thus 111 g of calcium chloride is produced.