Answer:
![Area = 58 \ units^2](https://img.qammunity.org/2023/formulas/mathematics/high-school/oviolk269030zg2wugcuzs5l9aly4jsfhj.png)
Explanation:
We can start by finding the third side of the triangle/the side of the square using the Pythagorean Theorem:
![a^2+b^2=c^2](https://img.qammunity.org/2023/formulas/mathematics/high-school/fdnnfwrccw5g60jmi691r5gcz9ekxf8waa.png)
In this case the side length of the square would be represented by the variable "c" as it is the hypotenuse:
![3^2+7^2=c^2](https://img.qammunity.org/2023/formulas/mathematics/high-school/v8ydhm35oaxp6ydzrgjmpn385fs35qlagn.png)
![9+49=c^2](https://img.qammunity.org/2023/formulas/mathematics/high-school/qt0al9on5ea3xdngjfezxgml4tecn371zu.png)
![c^2=58](https://img.qammunity.org/2023/formulas/mathematics/high-school/nvbbwv24pnlsc2dzct32rebge1x4f3z2yp.png)
![c=√(58)](https://img.qammunity.org/2023/formulas/mathematics/high-school/bg8ec96g0e5o34ml4k8siffahsykuvkv6c.png)
Since the area of a square is the side length square then...
![Area =( √(58) )^2](https://img.qammunity.org/2023/formulas/mathematics/high-school/f63l2bsirvccig2bf64fhyirz8fi43w00i.png)
The square root and the squared cancel out giving us...
![Area = 58 \ units^2](https://img.qammunity.org/2023/formulas/mathematics/high-school/oviolk269030zg2wugcuzs5l9aly4jsfhj.png)