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In a certain skyscraper, the elevator whisk you a restaurant in the skyscraper at a speed of 500 feet in 60 seconds. If the restaurant is 300 feet up, how long will it take you to reach the restaurant by elevator?

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\bf \begin{array}{ccll} feet&seconds\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 500&60\\ 300&x \end{array}\implies \cfrac{500}{300}=\cfrac{60}{x}\implies \cfrac{5}{3}=\cfrac{60}{x}\implies x=\cfrac{3\cdot 60}{5}
User Ryan Norbauer
by
8.3k points
1 vote

Answer:

The elevator will take you up at 300 feet in 36 seconds.

Explanation:

Let the time taken to go up 300 feet be = t seconds

Given is that the elevator takes you up at 500 feet in 60 seconds.

So, we can derive a relation as:


(500)/(60)= (300)/(t)

=>
500t=300*60

=>
500t=18000

t = 36 seconds

So, the elevator will take you up at 300 feet in 36 seconds.

User Celso Wellington
by
8.0k points
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